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b. Apabila ∶ = ∶ maka ∶ = ∶

Pembuktian :

∶ = ∶ ⇔ = ( )

⇔ = ( )

⇔ = ( )

, ∶ = ∶ ↔ ∶ = ∶ ( )

c. Apabila ∶ = ∶ ( + ) ∶ = ( + ) ∶

Pembuktian :

∶ = ∶ ⇔ = ( )

⇔ + = + ( ℎ )

⇔ ( + ) . = . ( + ) ( )

+ +
⇔ = ( )

, ∶ = ∶ ⇔ ( + ): = ( + ) ∶ ( )

d. Apabila ∶ = ∶ ( − ) ∶ = ( − ) ∶

Pembuktian :

∶ = ∶ ⇔ =

⇔ − 1 = − 1 ( )

⇔ − = −

− −
⇔ = ( )

, ∶ = ∶ ⇔ ( − ): = ( − ) ∶ ( )

BAB 1 Perbandingan 13