Page 19 - TUGAS UAS MEDIA PEMBELAJARAN E-MODUL WINDI SRINOVA RAMADHINI
P. 19
MODUL KIMIA STOIKIOMETRI
c = 1
➢ a = 2c
a = 2 x 1
a = 2
➢ a+2b = 2d
2+(2x1) = 2d
2+2 = 2d
4 = 2d
d = 4 : 2
d = 2
Sehingga persamaan reaksinya menjadi
2NaOH + H2SO4 → Na2SO4 + 2H2O (setara)
(Skor = 25)
4. aPb (NO3)2 + bNaCl → cPbCl2 + dNaNO3
ruas kiri = ruas kanan
Jumlah atom Pb a = c
Na b = d
N 2a = d
Cl b = 2c
O 6a = 3d
Misalnya a = 1 maka :
➢ a = c
c = 1
➢ 2a = d
2x1 = d
d = 2
➢ b = d
b = 2
➢ 6a = 3d
6 x 1 = 3 x 2
Sehingga persamaan reaksinya menjadi
Pb (NO3)2 + 2NaCl → PbCl2 + 2NaNO3 (setara)
(Skor = 25)
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