Page 78 - MODUL ELEKTRONIK LABFIS

CONTOH SOAL

Gaya Lorentz

K a w a t y a n g p a n j a n g n y a 1 m d i t e m p a t k a n d a l a m m e d a n m a g n e t

y a n g k u a t m e d a n n y a 0 , 0 1 T . B a g i a n k a w a t y a n g d i k e n a i m e d a n

m a g n e t h a n y a s e p a n j a n g 1 0 c m , d e n g a n a r a h a r u s d a l a m k a w a t

s e b e s a r 2 0 0 m A , m e m b e n t u s u d u t 3 0 ° t e r h a d a p m e d a n m a g n e t .

B e r a p a k a h b e s a r g a y a y a n g b e k e r j a p a d a k a w a t ?

Pembahasan

Diketahui :
L = 1 m

B = 0,01 T

I = 200 mA = 0,2 A
θ = 30°

Ditanya F?

Jawab :

S e b u a h k a w a t p e n g h a n t a r p a n j a n g n y a 2 m b e r a r u s l i s t r i k 1 0 m A

b e r a d a p a d a e m e d a n m a g n e t t e t a p 5 T . J i k a s u d u t a n t a r a m e d a n

m a g n e t d a n a r u s a d a l a h 9 0 ° , m a k a b e s a r g a y a l o r e n t z y a n g

d i a l a m i k a w a t p e n g h a n t a r t e r s e b u t a d a l a h …

Pembahasan
Diketahui :

L = 2 m

I = 10 mA = 0,01 A
B = 5 T

θ = 90°

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