Page 85 - Fundamental of Engineering Design
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Example 8
A steel column is 3m long and 0.4m diameter.it carries a load of 50MN.
Given that the modulus of elasticity is 200GPa, calculate the
compressive stress and determine how much the column is
compressed
Solution
A = π 2 = π 0.42 = 0.126m 2
4 4
50 106
6
σ= = = 397.9 x 10 Pa
0.126
σ
E= σ ε= = 397.9 106 = 0.001989
ε ε 200 106
δ
ε= δ = ε = 0.001989 x 3000mm=5.97mm
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