Page 35 - 21A_Kelompok 2_Bookchapter Fismod (Relativitas Khusus 2)_Revisi
P. 35
Jawab:
= −
1 = −
2
1
+ =
2
3
=
2
3
2
2
2 =
0
3
=
2 0
Sehingga,
3
= 0
2 0 2
√1 −
2
2 2 2 4
1 − = =
2 3 2 9
4
2 = 1 −
2 9
2 5
=
2 9
5
2
= √
9
1
= √5
3
32
