Page 13 - Bab_Listrik Magnet-dikonversi
P. 13
3
27×10
3×10
7
1 = 1 2 = 9 × 10 9 (5√2×10 −6 ) 2 = 50×10 −4 = 0,54 × 10 /
−2
7
2 = 2 = 9 × 10 9 3×10 −6 2 = 27×10 3 = 0,54 × 10 /
2 (5√2×10 −2 ) 50×10 −4
7
3 = 3 = 9 × 10 9 4×10 −6 2 = 36×10 −3 = 0,72 × 10 /
2 (5√2×10 −2 ) 50×10 −4
7
4 = 4 = 9 × 10 9 4×10 −6 2 = 36×10 −3 = 0,72 × 10 /
2 (5√2×10 −2 ) 50×10 −4
7
7
7
= 1 + 3 = 0,54 × 10 + 0,72 × 10 = 1,26 × 10 /
7
7
7
= 2 + 4 = 0,54 × 10 + 0,72 × 10 = 1,26 × 10 /
2
°
= √ + 2 + 2 ∙ ∙ ∙ cos 90
2
= √ + 2
= √(1,26 × 10 ) + (1,26 × 10 ) = 1,78 × 10 /
7
7 2
7 2
2. Dua buah muatan listrik terletak seperti gambar di bawah
ini. Berapakah besarnya kuat medan listrik pada medan P ?
E 1
P
E
1 2 0 0
20 cm
E 2
+ -
Q 1 = 3µC Q 2 = -4 µC
13