Page 279 - Buku Aljabar Linear & Matriks

» [L1,U] = lu (A)
L1 =
1.0000 0 0
0.6667 0.5000 1.0000
-1.0000 1.0000 0

U =
3 6 9
0 2 -2
0 0 -3

» [L,U,P] = lu (A)
L =
1.0000 0 0
-1.0000 1.0000 0
0.6667 0.5000 1.0000

U =
3 6 9
0 2 -2
0 0 -3

P =
1 0 0
0 0 1
0 1 0

atau P’ * L * U = A jadi P * L = L1

% membuktikan L*U = P * A

» X = L * U

X =
3 6 9
-3 -4 -11
2 5 2

» Y = P * A

Y =
3 6 9
-3 -4 -11
2 5 2

270 | K o m p u t a s i d e n g a n M A T L A B