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Jawab :

a. Rumus fungsi f(x) = x +2

b. Daerah asal = { 2, 3, 4, 5 }

c. Daerah hasil : f(x) = x + 2

untuk x = 2  f(x) = 2 + 2 = 4

x = 3  f(x) = 3 + 2 = 5

x = 4  f(x) = 4 + 2 = 6

x = 5  f(x) = 5 + 2 = 7

Jadi daerah hasil fungsi : { 4, 5, 6, 7 }

d. f(x) = 15 x + 2 = 15

x = 15 – 2

x = 13 Jadi nilai x = 13

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Adaptif