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Pembahasan :
a. f(x) = ½ x + 1
f(2) = ½ . 2 + 1 = 1 + 1 = 2
f(4) = ½ . 4 + 1 = 2 + 1 = 3
f(6) = ½ . 6 + 1 = 3 + 1 = 4
f(8) = ½ . 8 + 1 = 4 + 1 = 5
f(10) = ½ . 10 + 1 = 5 + 1 = 6
Jadi Range / daerah hasil / daerah
bayangan = { 2, 3, 4, 5, 6 }
b. Himpunan pasangan berurutan
{ (2,2), (4,3), (6,4), (8,5), (10,6) }
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Adaptif
