Page 43 - E-Modul Fluida Statis

KEGIATAN BELAJAR 2

Latihan Soal Hukum Pascal Latihan Soal Hukum Archimedes

Diketahui: Diketahui:
m = 81 kg air = 1 gr/cm
3
r1 = 2 cm = 2 x 10 m minyak = 0,8 gr/cm
-2
3
-2
r2 = 18 cm = 18 x 10 m
V air = 50% = 0,5 V
Ditanya : V minyak = 30% = 0,3 V
F1 = …?

Ditanya:
Jawab: b = …?
2
A1 = π r1
-2
A1 = π (2 x 10 m) Jawab:
2
-4
2
A1 = 4x 10 π m w = FA1 + FA2

2 m . g = air g V air + minyak g V minyak
A2 = π r2
-2
2
A2 = π (18 x 10 m) m = air V air + minyak V minyak
2
-4
A2 = 324x 10 π m b V = air V air + minyak V minyak
b V = (1 gr/cm ) (0,5 V) + (0,8
3
3
2
F2 = m.g = 81 kg (10 m/s ) = 810 N gr/cm ) (0,3 V)
3
b = 0,5 gr/cm + 0,24 gr/cm 3

3
b = 0,74 gr/cm
P1 = P2

=

=
( )′ ( )′

( )
=
( )′ ( )′
( − )′
F1 = . 810 N
( − )′
− ′
F1 = . 810 N
− ′
F1 = N