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(1 - 1) The First Derivative of a Function
                 Rules of Differentiation

                     The first derivative of the function   y =  ( x ) is denoted by any of the following symbols

                        dy        d             d

                                ,        ( y )     ,        ( x )     ,      '( x )     ,     y'
                        dx        dx            dx


                 1) Constant function   y = c ,  c           y' = 0
                                                                                        y    1    dy     1 2
                 2) Power rule          y = x ,  n           y' = n x  n – 1              x     dx   x 1
                                             n
                                                                                                  dy
                                                                                        y    x    
                                                                                                  dx  2  x
                 3) Constant × function   y = c × ƒ( x), c     y' = c × ƒ' ( x )




                 4) Sum or difference   y = ƒ ( x ) ± g ( x )   y' = ƒ' ± g'
                 5) Product rule        y = ƒ ( x )  g ( x )   y' = ƒ' g + g' ƒ
                 6) Quotient rule            ƒ x                    ƒ' g   g  ƒ '
                                               
                                            y                 y' =
                                               
                                             g x                       g  2

                             Example (1)
                                 Find the first derivative for each of the following functions:

                              1)  y   = 3
                                       4
                              2)  y   = x
                              3)  y   = 5 x  7
                                         3
                              4)  y   = 2 x  – 3 x + 5
                                          2
                              5)  y   = ( 3 x  + 1 ) ( 5 x + 2 )
                                       2 x
                              6)  y   =
                                      3x  5

                              Solution:
                              1)  y'  = 0
                                         3
                              2)  y'  = 4 x
                                             6
                              3)  y'  = 5  7 x = 35 x  6
                                         2
                              4)  y'  = 6 x  – 3
                                                               2
                                                                            2
                              5)  y'  = ( 6 x )( 5 x + 2 ) + ( 5 ) ( 3 x   + 1 ) = 45 x + 12 x + 5
                                                   
                                      2  3x  5   3 2 x    10
                              6)  y'  =           2       =         2
                                          3x  5         3x  5 




                 Calculus                                    12                                      Unit (1)
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