Page 138 - Grade 10 C.Math

cyjf, 4x = 4y – 8

cyjf, x = y – 2 ........ (i)

x
k]ml/ M

cyjf, 4(x + 10) = 5(2y - 2) ......... (ii)
Curriculum Development Centre
;dLs/0f (i) af6 ;dLs/0f (ii) df x = y - 2 /fVbf
4(y - 2 + 10) = 10y - 10

cyjf, 4y + 32 = 10y – 10

cyjf, 4y – 10y = -10 - 32

cyjf, -6y = -42

cyjf,

cyjf, y = 7

km]l/, ;dLs/0f (i) af6
x = 7 - 2 = 5

lbOPsf] leGg  x'G5 .

pbfx/0f 6
b'O{ cª\sn] ag]sf] Pp6f ;ª\Vofdf cª\sx¿sf] of]ukmn 8 5, olb ;f] ;ª\Vofaf6 36 36fOof]
eg] cª\sx¿sf] :yfg ablnG5 . Tof] ;ª\Vof slt xf]nf < kTtf nufpg'xf];\ .

;dfwfg

dfgf}F, Tof] b'O{ cª\sn] ag]sf] ;ª\Vof 10x + y xf] .

hxfF x / y j|mdzM b;sf] :yfg / Pssf] :yfgdf /x]sf cª\sx¿ x'g\ .
k|Zgsf] klxnf] ;t{cg';f/ x + y = 8

cyjf , x = 8 – y ......... (i)

k]ml/, bf];|f] ;t{cg';f/ 10x + y – 36 = 10y + x

cyjf, 10x – x = 10y - y + 36

cyjf, 9x = 9y + 36

135 ul0ft, sIff – 10