Page 28 - Grade 10 C.Math
P. 28

/ rj|mLo Aofh (C.I) = rj|mLo ld>wg (CA) –d"nwg (P)  = CA – P






                                                        x'G5
                       Curriculum Development Centre
                        To;} u/L oxL Aofh cw{ jflif{s ¿kdf u0fgf ul/G5 eg] Aofhb/ R% nfO{   / ;do T nfO{
                        2T n]lvG5 .

                        of] cj:yfdf rj|mLo ld>wg (CA)              x'G5 .



                        rj|mLo Aofh (CA)                 x'G5 .


                        To:t} olb Aofh Ps rf}yfO jif{ (3 dlxgf_df u0fgf ug]{ ul/Psf] ePdf Aofhb/ R/4% / ;do
                        4T x'G5 .

                                       /                      x'G5 .

                        olb k|To]s jif{sf] Aofhb/ km/s km/s ePdf s] xf]nf < ;d"xdf 5nkmn ug'{xf];\ .

                        pbfx/0f 1

                        ?= 1,500 sf] jflif{s 5% Aofhb/df 2 jif{kl5 rj|mLo Aofh slt x'G5 < ;"q k|of]u gu/L kTtf
                        nufpg'xf];\ .
                                                                            csf]{ tl/sf
                        ;dfwfg
                                                                                ]
                                                                                     ]
                                                                                   {
                                                                            klxnf jifsf Aofhb/ (A) = 5%
                        oxfF d"nwg (P) = ?= 1500
                                                                            bf];|f] jif{sf] Aofhb/ (b) = 5%
                        Aofhb/ (R) =5 % k|ltjif{
                                                                            rj|mLo Aofhb/ (R)
                        ;do (T) = 2 jif{                                    k|efjsf/L Aofhb/  (I) =
                        ca, klxnf] jif{df Aofh (T ) =                = ?= 75
                                              1
                        t;y{, bf];|f] jif{sf] d"nwg = ?= 1500 + ?=75 = ?= 1575

                        k]ml/ bf];|f] jif{sf] Aofh (I ) =      = ?= 78.75
                                                                                                 ]
                                            2                               rj|mLo Aofh = ?= 1500 sf 10.25%
                        ct rj|mLo Aofh (CI )    = I + I  = ?= 75 + ?= 78.75
                                               1   2

                                             =?= 153.75
                                                                                     = ?= 153.75


                       25                                                                 ul0ft, sIff – 10
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