Page 35 - CSA Chapter 2-part 1

Here's what we do with the 2 digit numbers. We find multiples of 8 ( 0,

8, 16, 24, 32, 40...) closest to the sum. For the first digit , we have 11.

The closest would be 8 so we subtract 8 to 11 to get 3. We subtracted it

by 8 once so we add 1 to the next digit. 10 + 1 will be 11. Find the

multiple closest to 11 which is 8. Perform the subtraction to get 3 and

carry 1 to the next digit once again. Repeat the process until all digits

are below 8.

The final answer is 1 3 3 3 (Octal).

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