Page 1 - first_project_testing

9/8/24, 1:19 PM myvinex.com/vinex_admin/php/print_pp.php?examId=1457&exam_type=0&type=new
VINEX

7. In stationary waves, distance between a
PHYSICS node and its nearest antinode is 20 cm.
The phase difference between two particles
1. A closed and an open organ pipe of same having a separation of 60 cm will be
length are set into vibrations
simultaneously in their fundamental mode A. Zero B. π/2 C. D. 3π/2
π
to produce 2 beats. The length of open
organ pipe is now halved and of closed 8. When a stationary wave is formed then its
organ pipe is doubled. Now find the frequency is
number of beats produced.
A. Same as that of the individual waves

2. Four harmonic waves of equal frequencies B. Twice that of the individual waves
and equal intensities I 0 have phase angles C. Half that of the individual waves
π
0, , 2π and . When they are superposed, D. None of these
π
3 3
the intensity of the resulting wave is nI 0 . 9. A standing wave having 3 nodes and 2
The value of is antinodes is formed between two atoms
n
having a distance 1.21 A o between them.
3. A 20cm long string, having a mass of 1.0g , The wavelength of the standing wave is
is fixed at both the ends. The tension in the o o o
string is 0.5N . The string is set into A. 1.21 A B. 2.42 A C. 6.05 A
vibrations using an external vibrator of D. 3.63 A o
frequency 100 Hz . Find the separation (in 10.If the length of a stretched sting is
cm) between the successive nodes on the shortened by 40% and the tension is
string. increased by 44%, then the ratio of the
final and initial fundamental frequencies is

A. 3 : 4 B. 4 : 3 C. 1 : 3 D. 2 : 1
,
11.If v v 2 and v 3 are the fundamental
1
4. For a certain organ pipe, three successive frequencies of three segments of stretched
resonance observed are 425, 595 and 765 string, then the fundamental frequency of
Hz. Taking the speed of sound to be the overall string is

340 ms −1 , find the length of the pipe, in
meter A. v 1 + v 2 + v 3 1 1 1 −1
B. [ + + ]
v 1 v 2 v 3
5. A stretched string of 1 m length, fixed at C. v v v D. [ v ] 1/3
1 2 3
v v
2
3
1
both ends, having a mass of 5 × 10 −4 kg is
′ ′
under a tension of 20 N. It is plucked at a 12.A closed organ pipe has a frequency n . If
point situated at 25 cm from one end. Find its length is doubled and radius is halved,
the stretched string would vibrate with a its frequency nearly becomes.
frequency (in Hz).
A. Halved B. Doubled C. Trebled
6. The equation of a stationary wave is D. Quadrupled
y = 0.8 cos( πx )sin 200πt ,
20 13.The length of two open organ pipes are l
where x is in cm and is in sec. The and (l + Δl) respectively. neglecting end
t
separation between consecutive nodes will correction, the frequency of beats between
be them will be approximately

A. 20 cm B. 10 cm C. 40 cm D. 30 cm A. v B. v C. vΔl D. vΔl
2l 4l 2
2l l

https://www.myvinex.com/vinex_admin/php/print_pp.php?examId=1457&exam_type=0&type=new 1/5