Page 62 - Cambridge Checkpoint Mathematics Coursebook 7_Slide 02
P. 62
5.4 Solving angle problems
Section 5.4 Solving angle problems
This diagram shows two straight lines crossing.
Angles labelled a° and c° are vertically opposite angles. Angles labelled b° a° d°
b° and d° are also opposite angles. c°
You can prove that vertically opposite angles are equal, as follows.
• a + d = 180 because they are angles on a straight line. Th erefore a = 180 – d. P
• c + d = 180 because they are angles on a straight line. Th erefore c = 180 – d.
• Since a and c are both equal to 180 – d, this means that a = c.
R
In the same way, you can show that b = d.
A special case of this is when two lines are perpendicular. S
All the angles are 90°.
Many equal angles are created when two parallel lines are crossed by a third line. Q
x PQ and RS are perpendicular.
a° b°
P d° c° Q
A line that crosses a pair of parallel
lines is called a transversal.
e° f°
R S
h° g°
y
Th e arrows drawn on the diagram show that PQ and RS are parallel. XY is a straight line.
Check the following facts.
• a + b = 180 Th ey are angles on a straight line. If you know one of the
• a = c and b = d Th ey are opposite angles. eight angles, you can
• a = e and b = f Th is is because PQ and RS are parallel. fi nd the other seven.
• a = c = e = g
• b = d = f = h
F Exercise 5.4 A D
P
1 Prove angle APC = angle DPB.
2 Three straight lines cross at one point. B
C
61°
d° 46°
c° a°
b°
Calculate the values of a, b, c and d. Give reasons for your answers.
60 5 Angles