Page 121 - steps 3b.pdf

• Answers 3b • • • • • • • • • • • • • • • • • 4

DRMs 5q, 60 DRM70
Open There are II possible nets for closed cubes if rotations and
reflections are excluded.
e DRM61
Open, although Tyrannosaurus Rex and a dodo should be
marked impossible.

DRM62
1 Answers will vary but should convey reasoning such as:
a Folse - it isn't impossible because two ports of the
spinner ore green.
b True - there are three orange and three yellow ports on
each spinner.
c True - there is only one blue port out of six.
d False - there is a better chance of spinning a colour
other than orange.
e Folse - there are four green ports but only two blue
ones. ~I.- -
f Folse - it is impossible to spin white as there are no
white parts. DRM 71
Solutions include:
DRM63
Open

e DRM64
1 x I 2 3 4 5 6 7 8 q 10
2 2 4 6 8 10 12 14 16 18 20
5 5 10 15 20 25 30 35 40 45 50
10 10 20 30 40 50 60 70 80 qO 100
2 a3x2 3x5 3x 10
b2x7 5x7 lOx 7
c8x2 qx2 lOx 2 DRM 72
d 8x 2 qx5 10 x 10 1 a 6
b 15
e lOx 5 10 x 6 7x5
c 18
3 x 4 10 2 q 5 I 7 6 8 3 d 105
2 8 20 4 18 10 2 14 12 16 6 e 162
10 40 100 20 qO 50 10 70 60 80 30
5 20 50 10 45 25 5 35 30 40 15 DRM 73
What is your favourite pop group?
DRM65
21: (2 x 6) + q; 41 - ( 5 x 4 ); 81- (6 x 10) 2 Open
46: (5 x 5) + 21 ;(7 x 2) + 32; (lOx 10) - 54;64 - (2 x q);
(8 x 5) + 6; (5 x 7) + II; 86 - (lOx 4) DRM 74
Possible solutions:
_ 13: (6 x 5) - 17; 5 + (4 x 2); (q x 10) -77; (2 x 10) -7;
., 2q-(8x2) 2 + 5 + 13
70: qs - ( 5 x 5); qO - (5 x 4); 100 - (lOx 3) 2 + 6 + 12
2+7+11
DRM66 2 + 8 + 10
al6 56 q6 3 + 4 + 13
3 + 5 + 12
b 35 85 135
c 20 120 320 3 + 6 + II
dl2 52 212 3 + 7 + 10
3+8+q
e 21 51 171
4 + 5 + 11
f 18 78 378
4 + 6 + 10
4+7+q
DRMs 67, 68
5+q+6
Open
5+8+7
DRM6q
5·6 + 3·q + 1·3 = 10·8 3·7 + 3·q + 1·3 = 8·q DRM 75
Open - encourage the children to check each other's
5·6 + 2·0 + 1·3 = 8·q 3·7 + 2-0 + 1·3 = 7·0
5·6 + 0·8 + 1·3 = 7·7 3·7 + 0·8 + 1·3 = 5·8 answers.
5·6 + 2·0 + 4·4 = 12·0 3·7 + 2·0 + 4·4 = 10·1
5·6 + 0·8 + 4·4 = 10·8 3·7 + 0·8 + 4·4 = 8·q
_ 5·6 + 3·q + 4·4 = 13·q 3·7 + 3·q + 4·4 = 12·0
., 5·6 + 3·q + 6·5 = 16·0 3·7 + 3·q + 6·5 = 14·1
5·6 + 2·0 + 6·5 = 14·1 3·7 + 2·0 + 6·5 = 12·2
5-6 + o·a + 6-5 = 12-q 3-7 + o-a + 6-5 = 11 -0

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