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• Rod multiplication Cuisenoirerods, metre rule • Different ways to multiply• • •

~=l•N:t"10~ Each rod hos been given a letter to represent its colour. The answer to 112 x 9 will app<oximote to 100 x 10 = 1000. ~=M•l:t"10~
Each rod hos been given a value to represent its length in centfmetres.
You can work out the actual answer to 112 x 9 in many different ways,
So for the green rod, we con soy g; 3.
some are shown here.
1 /2(100+/0+2)
PAGE 72 - block (b) 1J2X 9 -7 IEJ] 900 )( "/OO(foox"!) PAGE 73
1
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fS (2x "f )
x7 9~
q 1ooxq
'70 (/0•9)
pink(p}
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- ton (t) yel/ow (y) • D] Complete this sentence for each of these multiplications.
I think the answer will be about ...
b 376x2
c5x714
a 189x3
f 944 x 3
d 455 x 6
e 9 x 138
i 8 x 999
9 832 x 4
h 285 x 7
green (g)
dork green (d)
[Q Write on equation for each rod using its letter and value. red(r) rn Choose a way you like to work out the actual answers for W·
Are all your answers sensible?
, .. @] Half the answer cords to these multiplications are face-down.
(I] Work out the solutrons to these equations.
Work out what answers ore hidden on the face-down cards.
a tx9= b yx20= cdx7 = d bx12 = :=::::~:·::::;::
Show all your workings-out.
@] Complete these equations
a (tx9)+{yx5)=... b (px10)+(bx ... )=89
c (bx ... )-(rx6) = 51 d (gxB)+(dx5)= ...
.. ,.,
DJ 13] e (lx ... )+(px7) = 68 f (bx10) ... (yx7)=35
Make up 4 more equations with at least 2 sets of brackets.
Use letters to complete this equation
p=4 b=7 t= 8 y=5 g=3 @] in differ-ant ways to give:
d=6 r= 2 a 3 solutions between 50 and 70 b 3 solutions between 70 and 100.
CHALLENGE
[gJ • (.. x 4) + (g x 8) ; 48 • (Ix 4) - ( ... x 6) = 2 • ( ... x 8) + ( .. x 5) = 75
Decide the best way to find the value of the missing letters.
a 72 b 100 c 42 d 84
~ DJ
a ( t x q) + (y x 5) = q1 b (p x 1 O) + (b x 7) = 8q c (b x q) - (r x 6) = 51 Open: estimate the answer to each of the multiplications.
d (g x 8) + ( d x 5) = 54 e ( t x 5) + (p x 7) = 68 f (b x 10) - (y x 7) = 35
[gJ
a 567 b 752 c 3570 d 2730 e 1242 f 2832 g 3328 h 1qq5
Open: make up four more equations with at least two sets of brackets.
~
a q84 b 2070 c 624 d 2464 e 13q5 f 15q3 g 2870 h 2303
The face-down cards are: 2070, 624, 15q3, 2303
Open: complete the equation in different ways to give:
a three solutions between 50 and 70 Challenge
e.g. (d x q) + (r x 6) = 66 (y x q) + (p x 6) = 6q (g xq)+(y x6)=57
q36 x 1 = q36 468 x 2 = q36 312 x 3 = q36 234 x 4 = q36
b three solutions between 70 and 100 156 x 6 = q36 117 x 8 = q36 104 x q = q36
e.g. (d x q) + (g x 6) = 72 (t x q) + (r x 6) = 84 (y x q) + (b x 6) = 87
Challenge
( d x 4) + (g x 8) = 48 (t x 4) - (y x 6) = 2 (y x 8) +(b x 5) = 75