Page 3 - Presentación de PowerPoint
P. 3
Φ:(1/tan)3/4=37°
a = (1/tan) 8/5 =5
Cz = C(cos a)
Cx = C(cos a)(cosφ)
Cy = C(cos a)(sinφ)
∑ = 0
∑fz = C(sin 58) + B
∑fy = C(cos 58)(cos 37) = 0
∑fz = 2C(cos 58)= 40
C = 25,6N
B = 25,6N
∑fx = C(cos58)(sin37) + C(cos 58)(sin37) – D= 0
D = 2C(cos58)(sin 37)
D = 2(25,6)(cos 58)(sin 37)
D=15 N
