Page 126 - Distribusi peluang binomial
P. 126

M  N               P(X > 4) =                                    P(4 < X < 5)





  5
         1



 න                  X + 2                              = L
       20                                                             MBCN




 B  C  4                                1




                             =                  BC + MN MB
                                       2






 1  7                                   1           6                   7


      =  20  5 + 2 =  20     =         2 20                   +      20             (5 − 4)








 1  6                                     1 13



      =  20  4 + 2 =  20      =                                   (1)



                                         2 20



 MB = 5 − 4 = 1

                                          13




                               =
                                         40
   121   122   123   124   125   126   127   128   129   130   131