Page 161 - Distribusi peluang binomial

Contoh masalah

Jawaban untuk c yaitu “paling sedikit 2 kalkulator baik”

Cara 1

P(X  2) = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

= b(2; 5; 90%) + b(3; 5; 90%) + b(4; 5; 90%) +

b(5; 5; 90%)

= C (90%) . (10%) 5-2 + C (90%) . (10%) 5-3 + C (90%) . (10%) 5-4 +
4
3
2
5 2
5 3
5 4
C (90%) . (10%)
5 5 5 5-5

= (1/2)5(4). (0,81).(0,001) + (1/6)5(4)(3). (0,729).(0,01) +

(5). (0,6561).(0,1) + (1). (0,59049).(1)

= 0,0081 + 0,0729 + 0,32805 + 0,59049

= 0,99954

 0,9995