Page 53 - Distribusi peluang binomial

n(X = 0) = C = 8(7)(6)(5)/4(3)(2)1

8 4

= 7(2)(5)

n(X = 1) = C . C = 2. 8(7)(6)/3(2)1

2 1
8 3

= 2(8)(7)

n(X = 2) = C . C = 1. 8(7)/2(1)

2 2
8 2

= 4(7)

n(S) = C = 10(3)(7)

10 4