Page 38 - E-MODUL INTERAKTIF ASAM-BASA flip

Jawab:

[H⁺]= pH = - log [H⁺]
= √10⁻⁵ . 1x10⁻³ = - log 10⁻⁴

[H⁺] = √10⁻⁸ pH = 4
[H⁺] = 10⁻⁴

2.Basa lemah AgOH memiliki pH = 10 + log 5, jika Kb = 2,5 x 10⁻⁵.

Maka berapa konsentrasi basa?

Diketahui:
pH = 10 + log 5

Kb = 2,5 x 10⁻⁵

Ditanya:

Mb = ...?

Jawab:

pOH = 14 - pH
= 14 -(10 + log 5)

pOH = 4 - log 5

[OH¯]= 5 x 10⁻⁴

5 x 10⁻⁴ = √2,5 x 10⁻⁵ . Mb
(5 x 10⁻⁴)² = (√2,5 x 10⁻⁵ . Mb)²

25 x 10⁻⁸ = 2,5 x 10⁻⁵ . Mb

Mb = 10 x 10⁻³
Mb = 10⁻²

Mb = 0, 01 M

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