Page 9 - DIGITAL BOOK MUHAMMAD AZWARDI NASUTION

U = U 1

t

2 (n+ ) 1

1  
U = a +  2 (n + 1 ) 1−  b

t



1   1
U = a +  2 (n + 1− 2 ) b S = n (a + U n )

t


n

1 2
U = ( a2 + (n − 1 ) ) b 1 )
t
2 S = . n 2 (a + U n
n
1
U = a + a + (n − 1 )  b S = U . n

t
2 n t

1
U = a + U 
t
2 n