Page 29 - 6- اجابات نيوتن

‫إجابات‬
‫الفصل‬
‫الرابع‬

XL  2f L  2 22  700 1 400 
7 11

Z  R2  X2L  500

I  V  200  0.4A
Z 500

VL = I XL = 0.4  400 = 160 V
VR = I R = 0.4  300 = 120 V

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V = emf = NBA

V = 200  2  10-3  2  2  22  50
11 7

Vmax = 22.86 V Veff = 1616 V

Z  R2  (XL  XC)2

Z  (40)2  (110 140)2  50

I  V  16.16  03232 A
Z 50
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Z  R2  (XL  XC )2

Z  (8)2  (12  6)2  10

I  V  50  5 A
Z 10

VR = I R = 5  8 = 40 V
VL = I XL = 5  6 = 30 V

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XL  2f L  2 22  2  35 40 
7 11

Z  R2  XL2  50 
I  V  6  0.12A

Z 50
VR = I R = 0.12  30 = 3.6 V

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