Page 35 - 6- اجابات نيوتن

‫إﺟﺎﺑﺎت‬
‫اﻟﻔﺼﻞ‬
‫اﻟﺨﺎﻣﺲ‬

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 L  h
C

   Lx   x  1.5 1015  4
 Ly  y 3.75 1014 1

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E ‫ = ﻃﺎﻗﺔ اﻟﻔﻮﺗﻮن‬h = 6.625  10-34 90106 = 5.9625  10-26 J (١١)
(١٢)
Pw (‫ب‬
L = h

80  103 = 0.13  1031 ‫ﺛﺎﻧﻴﺔ‬/‫ﻓﻮﺗﻮن‬
 L = 596.2510-28

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eV = 1/2 mv2 1.6  10-19  600 = 1/2  9.1  10-31 v2
v = 14.526  106 m/s

PL = mv = 9.1  10-31  14.526  106 = 1.32  10-23 kg.m/s

λ h λ  6.62510-34 = 5.02  10-11 m
PL 1.32 10-23
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= h = 6.625 10-34 = 3.64  10-10 ‫ﻣﱰ‬
mv 9.11031  2 106

 = 3.64 ‫أﻧﺠﺴﱰوم‬

.‫ اﳌﺼﺎﺣﺐ ﻟﻺﻟﻜﱰوﻧﺎت > ﻃﻮل اﻟﺠﺴﻴﻢ‬

.‫ ﻜﻦ رؤﻳﺔ اﻟﺠﺴﻴﻢ‬

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