Page 93 - E-Modul Bentul Aljabar & Operasi Hitungnya
P. 93
3
2
18 3 18 = 2 × 3 × 3
2
3
18 : 6 =
6 2 6 = 2 × 3 × 2
2
2
6 (3 ) 18 3 6 2
=
6 2 2 × 3 × = 6
2
2
= 3
Coba Kerjakan !
2 3
2
(4 − 6 ): 2
2 3
4 − 6 2
2 3
2
(4 − 6 ): 2 =
2
2 3
2
4 6
= −
2 2
4 2−1 6
= ( × × ) − ( × × )
2 2
2
= − = 1; ≠ 0
0
2 3
4 − 6 2
2
2 3
(4 − 6 ): 2 =
2
2 × 2 ×
= −
2 2 
