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5.3        PROPORTIONS AND PROBLEM SOLVING
           Objective

           Solve Problems by Writing
           Proportions.
                                       Objective      Solving Problems by Writing Proportions
                                       Writing proportions is a powerful tool for solving problems in almost every field,
                                       including business, chemistry, biology, health sciences, and engineering, as well as in
                                       daily life. Given a specified ratio (or rate) of two quantities, a proportion can be
                                       used to determine an unknown quantity.
                                           In this section, we use the same problem-solving steps that we have used earlier
                                       in this text.

        PRACTICE 1                       Example 1 Determining Distances from a Map
        On an architect’s blueprint,    On a chamber of commerce map of Abita Springs, 5 miles corresponds to 2 inches.
        1 inch corresponds to 4 feet.   How many miles correspond to 7 inches?
        How long is a wall represented
             1
        by a 4  -inch  line on the                Nursery St  Dogwood S  SuccessSt  Carnation St  59
                                                   Camelia St
             4                                       Boxwood St  PansySt  Jasmine St  Dahlia St  435     Holly Oak
        blueprint?                                Nursery St  AzaleaSt Rose St  Violet St  Daisy St  A51  DavisCemetery R d  Long Branch  2 inches  5 miles  Cryer Rd  Vine St E Dr N
                                                                            Ahmeek Ln
                                                                                                       Vine St
                                                  Gurtner Dr  Jackie Ln  M artinLn  Kustenmacher Rd  Gordon Ave  36  Abita River  North St
                                             Tammany Trace  Miller Ln                            Oak St  Burvant St
                                                                     North St                 Forest Hill Dr
                                              Kustenmacher Rd    Holly St  Railroad Ave  Hickory St  Gum St  Main St   Pine St  Magnolia St  Level St  Indian Trail  Cherry  Julia St  V & M Rd
                                                    Kus t St  Kust St  Live Oak St  Grover St
                                                                           Cypress St
                                                                2nd St  Leveson St GroverSt  Regina St  Lange Rd
                                                                                      Peters S          Lawrence Ln
                                                                 3rd St  Bossier Av  Eads St  Eads S  Eads St
                                                                        Laurel St
                                                                    Maple St
                                                                St Mary St
                                                                            Andrews St
                                                  Kust St
                                                                    5th St  Hutchinson St
                                                                       6th St
                                                               59    St John St  Danny Park Dr
                                                                6th St
                                                           Pearl St  Keller St  Leveson S  7th St  St James St
                                                                7th St  St Joseph St  8th St  36
                                                          Mary S
                                                                                            0        1 mi
                                                                8th St
                                                              Haynes St
                                                            Orme St  Abita–Mandeville Hwy  Hickory Hwy
                                                                 St Mary St
                                                                  9th St  Nightwalk         0    1 km
                                                           Heintz  Gordon Ave  St  St Ann St  10th St
                                                                  10th St  10th St  9th St St Charles St
                                                           Poitevent Ave
                                                          Stire St  Keller St   Dundee Rd  ABITA SPRINGS
                                                                11th St
                                                           Millar St  Leveson St  St John St
                                                                 12th St
                                                Cherokee Dr
                                        Solution:
                                        1. UNDERSTAND. Read and reread the problem. You may want to draw a
                                           diagram.
                                                                            between 15 and 20 miles
                                                            15 miles
                                                                                  20 miles
                                                     5 miles  5 miles  5 miles  5 miles =a little over 15 miles
                                                    2 inches  2 inches  2 inches  2 inches =7 inches
                                                                                   8 inches
                                                            6 inches
                                                                            7 inches
                                           From the diagram we can see that a reasonable solution should be between 15
                                           and 20 miles.
                                        2. TRANSLATE. We will let  n represent our unknown number. Since 5 miles
                                           corresponds to 2 inches as n miles corresponds to 7 inches,we have the proportion
                                           miles    :     5  =  n    ;  miles
                                           inches   :    2   7   ;    inches
                                        3. SOLVE: In earlier sections, we estimated to obtain a reasonable answer.
                                           Notice we did this in Step 1 above.
                                                  5  =  n                                                           Copyright 2012 Pearson Education, Inc.
                                                  2     7
        Answer
        1. 17 ft
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