Page 171 - Basic Electrical Engineering

Converting current source of 6 A connected across the 2 Ω resistor, the
equivalent voltage source is represented as shown.

Figure 2.73

Now, we will calculate the open circuit voltage V across terminals A and
oc
B. Applying KVL in the loop,

15 − 4 I − 2 I − 12 = 0

or, − 6I = − 3

or, I = 0.5 A

Since no current flows through the 3 Ω resistor, V AB = V OC = V CD .

V AB =12 + 2I

= 12 + 2 0.5

= 13V

Point C is at a higher potential than point D. Hence point A is at a higher
potential than point B. Current through the load resistor will flow from A to

B.

Current through the load resistor