Page 586 - Basic Electrical Engineering

4 W + W = 8.2 kW = 8200 W (ii)
c
cu
From (i) and (ii),

W = 1923 W
c

and

W = 507 W
cu

Example 6.14 The equivalent circuit parameters of a 300 kVA, 2200/200 V,
50 Hz single-phase transformer are: primary winding resistance, R = 0.1 Ω;
1
secondary winding resistance, R = 0.01 Ω; primary leakage reactance, X =
1
2
0.4 Ω; secondary leakage reactance, X = 0.03 Ω; resistance representing core
2
3
3
loss, R = 6 × 10 Ω, magnetizing reactance X = 2 × 10 Ω. Calculate the
m
c
voltage regulation and efficiency of the transformer at full load at 0.8 power
factor lagging.

Solution:

Figure 6.27

We will consider E = 2200 V and E = 220 V
1
2

Transformation ratio,