Page 14 - Revista EPRA NOTARIO
P. 14
Balanceo por REDOX
−2
0
6
4
−2 + 2 →
2
3
S → S
6
4
3 → 2 −2
2
3
S → S + 2e¯
4
6
12¯ + 3 → 2 3 −2
2
12 [S → S + 2e¯]
4
6
]
2 [12¯ + 3 → 2 3 −2
2
6
12 → 12 + 24¯
4
0
24¯ + 6 → 4 3 −2
2
----------------------------------------------------------------------------
6
0
24¯ + 6 + 12 → 12 + 24¯ + 4 3 −2
4
2
0
6
6 + 12 → 12 + 4 3 −2
2
4
0
−2
4
6
12 2 −2 + 6 2 → 12
3
6
4
2 2 −2 + 0 → 2 3 −2
2
2 S 2
6 O 6
