Page 34 - MergedFile

Assume, Rate of upstream = X kmph Let the Cost Price be x.
Rate of downstream = Y kmph Then 92% of x = 368
30 44 92
Then + = 10 -----(i) × = 368
100
And 40 + 55 = 13 -----(ii)  x = 368 × 25 = 400
23
On solving (i) and (ii), we get X = 5 and Y = 11 Cost Price = Rs.400: Gain = 15%
So, Rate of upstream = 5 km/hr Selling Price = 115 × 400 = . 460
Rate of downstream = 11 km/hr 100
1
Rate of current = × (11 − 5)) km/hr = 3 km/hr
2 66. Sol: (b)
59. Sol: (d) Distance = 110 m.
Let the sum be x. Relative speed = 60 + 6 = 66 Kmph
Then, Simple Interest = 40% of x =2x/5; = 66 × 5 m/sec
Rate = 5% 55 18
Simple Interest = PNR/100 = m/sec
3
Time = 100 × 2 × 1 Therefore time taken to pass the train = 100 × 3
5 ( ×5) 55
= 8 years. = 5.45 ≈ 6s
60. Sol: (c) 67. Sol: (c)
Correct Sum = (36 × 50 + 48 - 23) = 1825. 3 men or 4 women can plough the field in 43 days.
Correct mean = 1825/50 = 36.5 That is, 3 men = 4 women.
61. Sol: (c) 1 man = 4/3 women.
(38.9×10)−(42×6) 7 men = 28/3 women.
Average of last 4 matches =
4 7 men and 5 women = (28/3) + 5 = 43/3 women.
(389)−(252) Given: 4 women can plough field in 43 days.
= = 34.25
4 So, 1 women can plough in = 43 × 4 days.
62. Sol: (b) Hence,
From the given question, 43/3 women can plough = (43 × 4 × 3)/43 = 12 days.
25
× × 3 68. Sol: (a)
4
100 = Let the cost price of two watches be x and y
8
3
 25 = ⇒ R = 6% For 1 watch,
st
400 8 105
63. Sol: (b) × 100 = 3750
Assume, Cost price = x x = 3572
nd
Selling price = 1.25x For 2 watch,
New Cost price = x - 200 y × 95 = . 3750
Selling price = 1.25x - 200 100
y = Rs.3947
Now,
Total cost price = 3572 + 3947
1.3(x-200) = 1.25x - 200 = Rs.7519
x = 1200 Total selling price = 3750 + 3750
64. Sol: (d) = RS.7500
Relative Speed = (36+45)Km/hr
Loss = 7519-7500 = Rs.19
= 81Km/hr Loss % = 19 ×100
= (81 × 5 ) m/sec 7519
18 = 0.25% loss
= (45/2) m/sec 69. Sol: (d)
45
Length of the train = × 8 70. Sol: (c)
2
= 180 m 71. Sol: (d)
65. Sol: (c) 72. Sol: (d)
73. Sol: (d)