Page 143 - Services Selection Board (SSB) Interviews

Distance and Direction 139
2. (c) figure, option 3 is correct, 50 km to the east and 40
km to the north.
4. (c)

Note: According to Pythagoras’ theorem, for a rightangled
triangle.
C
5. (a) From the above we can conclude that option (c)
is correct.
(a) Total Distance travelled by Kartikay from starting
point till last signal=(1 + 1 + 2 + 4 + 1)km = 9
A B km.

2
2
BC = AB + AC 2 6. (a) As Kartikay started heading north, he will be 3.0
km to the west and 2.0 km to the south if one
2
BC = AB + AC 2 guard with red cap and two gaurds with green
( ST 2 + 2 ) =TF ( 40 2 + 2 ) = 30 =2500 50km caps were placed at the first signal point.
7. (c) As Kartikay started heading south, he will be
3. (c) For the case when 1st signal were 1 red and 2 3.0 km to the west and 4.0 km to the south.
green light, the surface diagram will be as given 8. (c) From the given information we can draw the
below. diagram:

TF = 50 km; ST = 40 km Considering the above From the diagram we can conclude that finally he is
13 kms in the North-East direction from the starting
point.