Page 21 - BS Matematika Kelas 5 Materi 1
P. 21

Perkalian Pecahan Campuran dengan Bilangan Asli

                      Contoh                Penyelesaian
                          2                     2        7        7 × 4     28     3
                      1. 1  × 4 = ...       1. 1  × 4 =   × 4 =          =      = 5
                          5                     5        5          5       5      5
                                                    4
                              4
                      2. 3 × 1  = ...       2. 3 × 1  = 3 ×  11  =  3 × 11  =  33  = 4 5
                              7
                                                                              7
                                                                                    7
                                                                     7
                                                    7
                                                              7







                    Kerjakan perkalian pecahan berikut!

                          2                    5                        3                         4
                     . 1  2  x 5 =  ...    . 4  1  x 4 =  ...   . 7  5 x1  =  ...        . 9  12 x1  =  ...
                          3                    7                        7                         9
                          4                    7                         9                          3
                                                                                                x
                     . 2  1  x 2 =  ...    . 5  1  x 2 =  ...   . 8  6  x1  =  ...     10 . 100 1      =  ...
                          5                    9                        10                         25
                          5                      7
                     . 3  2  x 6 =  ...    . 6  4  x  =  ...
                          8                      9


                     Perkalian Pecahan Campuran dengan Pecahan Biasa

                     Contoh                Penyelesaian
                           1   1                 1   1    5   1     5 x1     5
                       . 1  1  x  =  ...    . 1  1  x  =    x    =       =
                           4   6                 4   6    4   6     4 x 6   24
                          1     4              1     4    1    9    1 x 9    9
                       . 2  x1    =  ...    . 2   x1    =    x   =        =
                          4     5               4    5    4    5    4 x 5   20













                    Selesaikanlah perkalian pecahan berikut!

                          2   1                  2   2                2    3                  4    7
                     . 1  2  x   =  ...     . 4  1  x   =  ...     . 7  x1    =  ...      . 9   x1    =  ...
                          3   6                  7   3                5    7                  5    8
                          4   1                  7   2                3     3                5     3
                     . 2  2  x   =  ...     . 5  1  x  =  ...      . 8  x 2    =  ...    10 .   x1    =  ...
                          5   8                  8   5                4    10                 8    4
                          2   2                2     5
                     . 3  1  x   =  ...     . 6   x 1  =  ...
                          7   5                3     9






               20                                                Senang Belajar MATEMATIKA untuk SD/MI kelas V
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