Page 15 - MODUL 3

Modul Matematika Umum Kelas XI KD 3.10

2
Misalkan = 3 + 5
= 6
1
=
6
1
2
∫ 6 √3 + 5 = ∫ 6 1 ⁄ 2
6
1
= ∫ ⁄ 2
1 1 +1
= 2 +
1 + 1
2
1 3
= ⁄ 2 + 3
⁄ 2
2
= √ +
3
2
2
2
= (3 + 5) √3 + 5 +
3
8. D
Pembahasan:
3x −1
 (3x − 2x + 7) 7 , misal = 3 − 2 + 7
2
2
= (6 − 2)
= 2(3 − 1)
1
=
2(3 −1)
3 −1 1
−7
∫ 7 = ∫(3 − 1)
2
(3 −2 +7) 2(3 −1)
1
−7
= ∫
2
1 1
= . −7+1 +
2 −7 + 1
1 1
= . − −6 +
2 6
1
= − +
−6
12
1 −6
2
= − (3 − 2 + 7) +
12
1
= − +
2
12(3 − 2 + 7)
6

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