Page 71 - Materi Gelombang Bunyi Kelas XI
P. 71
16 = + 10 log 16
1
2
16 = + 10 log 4
1
16 = 70 + 10 . 2.0,6
16 = 70 + 12
16 = 82
Memeriksa kembali solusi yang diperoleh
a. Pembuktian terbalik
2
Jika 16 = 82 , = 16, = 10 −12 / , maka :
0
16 = + 10 log 16
1
2
82 = + 10 log 4
1
82 = + 10 . 2.0,6
1
82 = + 12
1
= 82 − 12
1
= 70
1
= 10 log
1
0
70 = 10 log
10 −12 2
⁄
7
log 10 = log
10 −12 2
⁄
7
10 =
⁄
10 −12 2
66
