Page 17 - Modul 2 Sumber Medan Magnet
P. 17
Modul Sumber Medan Magnet
Contoh Soal
Jawab: Kita gambarkan kasus di atas sbb.
(4 10 −7 )(5)
−5
0 1
a) = 2 = 2 (0,1) = 1 10 (keluar bidang)
1
b) 2 = = (8)(1 10 ) = 8 10 / (ke arah
−5
−5
2 1
kawat 1)
(4 10 −7 )(8)
0 2
c) = 2 = 2 (0,1) = 1,6 10 −5 (masuk
2
bidang)
d) 1 = = (5)(1,6 10 −5 ) = 8 10 −5 / (ke arah
1 2
kawat 2)
8
