Page 466 - eProceeding - IRSTC & RESPEX 2017

M. Dwi Trisna / JOURNAL ONLINE JARINGAN COT POLIPD

bb. Radius of blades curvature, rb (mm)

 d 


(28)
rb    (29)
cos    


1
cc. Radius of blades curvature centre, rp (mm)
rp  rb  R  2. rb R. 1 cos  (30)
2
2
1
1
=148.2017073
dd. Thickness of baldes:
T = R 3 – rp (31)
= 6.32 mm ≈ 6.6 (mm)

bb. Average curvature angle:
 = (  +  )/2 (32)
ff. Number of blades

360
 0   26 pieces (33)
Z

gg. Distance between the bales
D . 
  1
0
Z (34)
δ 0 = 48,30769231 (mm).
Number of contacted blades

85
O
Z  . 26; transmit angle 85 . (35)
360
Z = 6,138 ≈ 6 pieces

hh. The shape of transmit pipe
0
0
0
The radius need to calculation every 5 dari  = 0 s/d 90 .
a. K = tan 
1
b. Chenge to angle value,  360 = 2
1
c.  = e tan α (θ)rad.
0
d. R 0 =  0 .R
1

Figure-7. Wheel blades. Figure-8. Transmit pipe Figure-9. Wheel

ii. Angle of turbine transmit
0
Based on simulation,  = 85 R 0 = 278,67 mm.
465 | V O L 1 0 - I R S T C 2 0 1 7 & R E S P E X 2 0 1 7