Page 227 - C:\Users\azizu\Documents\Flip PDF Professional\Matematics-Form-1-1\
P. 227

Self Practice       9.3b

               1.                                         2.                   C
                                                                        B     y
                             S       R
                                                                    A
                              115° 118°                               84°         x   96°  D
                            68°           x                                          E
                         P               Q  T                               F


                   In the diagram, PQT is a straight           In the diagram,  ABC and DEF are straight
                   line. Calculate the value of x.             lines. Calculate the values of x and y.



                     How do you solve problems involving                           LEARNING
                    quadrilaterals?                                                      STANDARDS
                                                                               Solve problems
                            6                                                  involving quadrilaterals.

                                  P               U
                                      V            T
                                    y    x             S
                                                   72°





                                 Q                R

       CHAPTER
               In the diagram, PQRU is a square and QRSV is a parallelogram.
       9
               PVR is a straight line. Find the values of x and y.
                                                                                An architect uses the
                                                                                knowledge of polygons
               ∠PQR = 90° dan PQ = QR                                           to design a building.


                                90°
               Thus,  ∠QRV =
                                 2
                            x = 45°      x = ∠QRV

                   ∠  QVS + 72°  = 180°                    V           S
                         ∠  QVS  = 180° – 72°                 x    72°
                                 = 108°

               Therefore, ∠QVR + x  = 108°
                              ∠QVR  = 108° – 45°        Q           R
                                      = 63°

               Hence, y = 180° – 63°
                         = 117°

           216
           Chapter 9



       09 TB Math F1.indd   216                                                                       11/10/16   12:18 PM
   222   223   224   225   226   227   228   229   230   231   232