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Self Practice  3.2b          Self Practice  3.2h          3.
                                           1.  (a)  16    (b)  0.75               2
                     3
               1.  (a)   8  ×  8  ×  8                4
                                                (c)  –      (d)  0.4               4
                     = 8                             125
                                             (e)  –1     (f)  0.018
                     3
                  (b)  0.3  ×  0.3  ×  0.3           9         56
                                                (g)  –      (h)               Area of the square
                     = 0.3                           4          3
                                                                                   1
                                                (i)  –3                       = 2 ×   × 4 × 2
                            3
                  (c)  3 1 –   1 2                                                 2 2
                         2                      Mastery    3.2                = 8 unit
                                             1.  (a)  No                      Length of side of the square
                         1
                     = –                        (b)  Yes                      =   8 unit
                         2
                                                   343 = 7 × 7 × 7
                 Self Practice  3.2c            (c)  Yes                   4.  400 = 2 × 2 × 5 × 2 × 2 × 5
                                                   1 000= 2 × 5  × 2 × 5  × 2 × 5    Length of side = 2 × 2 × 5
               1.  (a)  216   (b)  –343                                                  = 20 m
                        8                    2.  3 375 =  3 × 5  ×  3 × 5  ×  3 × 5
                  (c)  –      (d)  –0.027
                       729                                               5.  (a)  512 =  2 × 2 × 2  ×  2 × 2 × 2
                                                3
                     2 197                       3 375 = 15
                  (e)                                           64                   ×  2 × 2 × 2
                      125                    3.  (a)  –125   (b)
                                                               125
               2.  (a)  17 576   (b)  –132.651     (c)  –   343    (d)  –32.768  Prime factors can be grouped
                                   5 832             216                         into three identical groups.
                  (c)  0.027   (d)  –           (e)  5      (f)  – 8
                                   1 331                                         
                      13 824                    (g)  9      (h)  –30          (b)  512
                  (e)
                       125                         2             4               = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2
                                                (i)         (j)  –
                                                   5             7               Prime factors cannot be
                 Self Practice  3.2d            (k)  – 0.8   (l)  1.1            grouped into two identical
               1.  21                                                            groups.
                                             4.  (a)  8 242 408
               2.  14                           (b)  –5 451.776            6.  6 m
               3.  (a)  3     (b)  –5           (c)  0.000068921
                  (c)  7      (d)  –10          (d)  –  4 913              7.  (a)  10 cm  2
                      2            1                 343                      (b)  100 cm
               4.  (a)        (b)  –            (e)  3.26   (f)  6.00
                      5            3                                       8.  (a)  (i)  RM3.20
                      2           5             (g)  – 0.98   (h)  – 0.86
                  (c)         (d)                                                (ii)  RM20.00
                      3           4          5.  (a)  27    (b)  –1 000       (b)  Number of 20 sen coins with
                  (e)  0.1    (f)  – 0.4        (c)  3 375   (d)  –1             an amount of RM60
                  (g)  – 0.6   (h)  0.07        (e)  4      (f)  7                 60
                 Self Practice  3.2e            (g)  –9     (h)  2               =  0.2
                                                                 3
               1.  (a)  2.47   (b)  – 4.20   6.  (a)  50 mm   (b)  50            = 300
                  (c)  5.48   (d)  0.92      7.  (a)  2.09   (b)  – 80           300 is between 289 and 324,
                  (e)  –1.12                       24                            that is,  
                                                                                       300 is between
                                                (c)         (d)  12              
                                                                                         324 .
                 Self Practice  3.2f               25            19               289 and  
                                                (e)  –225   (f)  –               
                                                                                  300 is between 17 and 18.
               1.  (a)  8                                        21
                  (b)  –1 000                  Let’s Practise                    Therefore, the measurement
                  (c)  8 000                                                     of the largest square that can
                  (d)  –64 000               1.  4, 81, 49                       be arranged is 17 × 17.
               2.  (a)  2     (b)  4              36                       9.  (a)  112
                                                           3
                  (c)  –5     (d)  –3        2.       – (– 0.1)               (b)  No.
                                                  25
                 Self Practice  3.2g               6                             112 is not a perfect square.
                                                =     – ( – 0.001  )
               1.  Not enough.                     5                       10.  10, 13, 17
                  The length of the wire needed is   1 201
                  156 cm.                       =  1 000
             310
            Answers

       14 Ans Math F1.indd   310                                                                      11/10/16   12:23 PM
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