Page 321 - C:\Users\azizu\Documents\Flip PDF Professional\Matematics-Form-1-1\
P. 321
Self Practice 3.2b Self Practice 3.2h 3.
1. (a) 16 (b) 0.75 2
3
1. (a) 8 × 8 × 8 4
(c) – (d) 0.4 4
= 8 125
(e) –1 (f) 0.018
3
(b) 0.3 × 0.3 × 0.3 9 56
(g) – (h) Area of the square
= 0.3 4 3
1
(i) –3 = 2 × × 4 × 2
3
(c) 3 1 – 1 2 2 2
2 Mastery 3.2 = 8 unit
1. (a) No Length of side of the square
1
= – (b) Yes = 8 unit
2
343 = 7 × 7 × 7
Self Practice 3.2c (c) Yes 4. 400 = 2 × 2 × 5 × 2 × 2 × 5
1 000= 2 × 5 × 2 × 5 × 2 × 5 Length of side = 2 × 2 × 5
1. (a) 216 (b) –343 = 20 m
8 2. 3 375 = 3 × 5 × 3 × 5 × 3 × 5
(c) – (d) –0.027
729 5. (a) 512 = 2 × 2 × 2 × 2 × 2 × 2
3
2 197 3 375 = 15
(e) 64 × 2 × 2 × 2
125 3. (a) –125 (b)
125
2. (a) 17 576 (b) –132.651 (c) – 343 (d) –32.768 Prime factors can be grouped
5 832 216 into three identical groups.
(c) 0.027 (d) – (e) 5 (f) – 8
1 331
13 824 (g) 9 (h) –30 (b) 512
(e)
125 2 4 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2
(i) (j) –
5 7 Prime factors cannot be
Self Practice 3.2d (k) – 0.8 (l) 1.1 grouped into two identical
1. 21 groups.
4. (a) 8 242 408
2. 14 (b) –5 451.776 6. 6 m
3. (a) 3 (b) –5 (c) 0.000068921
(c) 7 (d) –10 (d) – 4 913 7. (a) 10 cm 2
2 1 343 (b) 100 cm
4. (a) (b) – (e) 3.26 (f) 6.00
5 3 8. (a) (i) RM3.20
2 5 (g) – 0.98 (h) – 0.86
(c) (d) (ii) RM20.00
3 4 5. (a) 27 (b) –1 000 (b) Number of 20 sen coins with
(e) 0.1 (f) – 0.4 (c) 3 375 (d) –1 an amount of RM60
(g) – 0.6 (h) 0.07 (e) 4 (f) 7 60
Self Practice 3.2e (g) –9 (h) 2 = 0.2
3
1. (a) 2.47 (b) – 4.20 6. (a) 50 mm (b) 50 = 300
(c) 5.48 (d) 0.92 7. (a) 2.09 (b) – 80 300 is between 289 and 324,
(e) –1.12 24 that is,
300 is between
(c) (d) 12
324 .
Self Practice 3.2f 25 19 289 and
(e) –225 (f) –
300 is between 17 and 18.
1. (a) 8 21
(b) –1 000 Let’s Practise Therefore, the measurement
(c) 8 000 of the largest square that can
(d) –64 000 1. 4, 81, 49 be arranged is 17 × 17.
2. (a) 2 (b) 4 36 9. (a) 112
3
(c) –5 (d) –3 2. – (– 0.1) (b) No.
25
Self Practice 3.2g 6 112 is not a perfect square.
= – ( – 0.001 )
1. Not enough. 5 10. 10, 13, 17
The length of the wire needed is 1 201
156 cm. = 1 000
310
Answers
14 Ans Math F1.indd 310 11/10/16 12:23 PM