Page 42 - E-modul Fluida Statis Berorientasi Problem Based Learning
P. 42
Pembahasan Soal Latihan
1. Diketahui :
L = 10 cm = 0,1 m
g = 9,8 m/s2
massa kawat = mk = 0,3.10-3 kg
massa beban = mb = 0,2.10-3 kg
Ditanyakan:
γ ?
Jawab :
F = W kawat + W beban
= mk. g + mb . g
-3
-3
= 0,3.10 .9,8 + 0,2.10 .9.8
-3
= 0,5.10 .9,8
-3
= 4, 90.10 N
=
2
= 4,90.10 −3
2.0,1
-2
= 2,45 . 10 N/m
2. Diketahui :
L = 10 cm = 0,1 m F = 4 . 10 -3 N
Ditanyakan:
γ = …?
Jawab :
=
2
= 4 . 10 −3
2. 10 −1
-2
= 2 . 10 N/m
3. Diketahui :
-5
R = 10 m
-3
γ = 72,8.10 N/m
θ = 0 o
g = 10 m/s 2
Ditanyakan :
h = …?
Jawab :
h = 2γ cos ρ g. R
-3
= 2. 72,8.10 . 1. 1000. 10. 10 -5
= 145,6.10 -4
-2
= 1,456 . 10 m