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02212032/CAPE/SPEC/MS/2017
                                                          - 3 –

                                                       CHEMISTRY
                                                  UNIT 2 — PAPER 032
                                                      MARK SCHEME
                                                                                                   KC    UK    XS
                     Question 2

                     S.O.: Module: 2 ----2.4, 2.5

                      (i) Pale yellow  pink tinge                              [1 mark]                      1

                      (ii)




                                       Burette readings KMnO 4 /H     +


                           Reading/cm  3            1             2             3



                       Final                     11.50         17.20          31.50


                       Initial                    0.50          6.70          20.90
                                                                                                              4


                       Difference                11.00         10.50          10.60


                      Correct burette readings  =   [4 marks]


                                 (If one incorrect                =   3 marks)
                                   (If two incorrect              =   2 marks)

                                 (If THREE incorrect              =   1 mark)



                                   (More than THREE incorrect  =   0 marks)


                                    Volumes recorded to 2 decimal places




                              10  5 .  10  6 .
                      (iii)              = 10.55 cm  3                                        [1 mark]
                                  2                                                                     1

                                                                     -3
                                              -
                       (iv)  Conc. of MnO4 (aq) = 0.02 mol dm
                                                                                 -3
                                                      -
                            No. of moles of MnO4  = (10.55 x 0.02 x 10 )

                                                   2+
                                                                                         -3
                            No. of moles of Fe (aq) = (5 x 10.55 x 0.02 x 10 )

                                                                         [1 mark]


                                                    2+
                                                                    3
                            No. of moles of Fe (aq) in 1 dm

                                                        5 x 10 . 55 x  . 0  02 x 10  3
                                                 =
                                                                20                                      3
                                                                    -2
                                            =    5.275 x 10  mol dm           -3        [1 mark]

                                   2+
                                                                               -3
                      Conc. of Fe   = (5.275 x 10       -2  x 56) =  2.95g dm   [1 mark]
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