Page 32 - E-MODUL FUNGSI EKSPONENSIAL DAN LOGARITMA X AISYAH AMINI
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5. 4√20 − 2√45

                      6. 4√6(√3 + 5√2)
                      7. (3√2 + √6)(3√2 − √6)



                         Penyelesaian:



                      1.  √48 = √16 × 3 = √16 × √3 = 4√3
                      2. 2√162 = 2√81 × 2 = 2√81 × √2 = 2 × 9 × √2 = 18√2

                      3. 5√3 + 2√3 = 7√3
                      4.  √108 + √48 = √36 × 3 + √16 × 3 = 6√3 + 4√3 = 10√3

                      5. 4√20 − 2√45 = 4√4 × 5 − 2√9 × 5 = 4 × 2√5 − 2 × 3√5 = 8√5 −

                         6√5 = 2√5

                      6. 4√6(√3 + 5√2) = 4√6  × √3 + 4√6 × 5√2 = 4√9 × 2 + 20√4 × 3 =
                         4 × 3√2 + 20 × 2√3 = 12√2 + 40√3

                                                                 2
                      7. (3√2 + √6)(3√2 − √6) = (3√2) − 3√2 × √6 + 3√2 × √6 −
                                                      2
                               2
                                            2
                         (√6) = (3√2) − (√6) = 18 − 6 = 12

                      Sederhanakanlah dan nyatakan dalam bentuk akar

                                1 2
                            2
                     1.  (   3 .    2)
                                 5 2
                            3
                     2. (   4 .    4)


                      Penyelesaian :



                            2    1 2       2 1 2        4 3 2       7 2      7
                      1.  (   3 .    2) = (   3 2) = (   6 6) = (   6) =    3 = √   =     . √  
                                            +
                                                                                  3
                                                         +
                                                                                                3
                                                                                            2
                                                                                      7
                            3    5 2      3   5
                      2. (   4 .    4) =    2 .    2 = √   .    =      √    
                                                                   2
                                                           5
                                                       3





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