461 10.4 (ideal gas law) 1 atm 0 °C 273.15 K STP (Ideal gas) 1 2 (10.9) P atm) V L) PV = nRT (10.9) n mol) T K) R 0.082058 L·atm/K·mol) STP 1 atm 0 °C 273.15 K 1 STP 10.9 1 x V = 1 x 0.082058 x 273.15 V = 22.4 L 1 STP 22.4 L