462
5 3 12 3 mL 1L
P 1 atm mL = 0.097 L 37 °C K
0 °C 273.15 K
37 °C 273.15 37 310.15 K
.
1atmx0.097L = nx(0.082058Latm/Kmolx310.15K)
(1 atm x 0.097 L)
STP 22.4 L STP
n=
n = 3.83mol
1
mol/Lsubstrate
(0.082058 L atm/K mol x 310.15 K)
=
= 85.79 L/Lsubstrate