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100 Problems & Solutions Trang 141
var j :integer;
begin
for j:=dong[i-1]+1 to N-5+i do
begin
dong[i]:=j;
if i=5 then kiemtra
else thu(i+1);
if ok=false then exit;
end;
end;
procedure lam;
var i,j,x,y,u,v,k :integer;
begin
for i:=1 to dem do
for j:=dem downto 1 do
for x:=1 to dem do
for y:=dem downto 1 do
begin
for u:=1 to 5 do
for v:=1 to 5 do a[u,v]:=w[i,u,v];
for u:=1 to 5 do
for v:=1 to 5 do a[u,5+v]:=w[j,u,v];
for u:=1 to 5 do
for v:=1 to 5 do a[5+u,v]:=w[x,u,v];
for u:=1 to 5 do
for v:=1 to 5 do a[5+u,5+v]:=w[y,u,v];
fillchar(c,sizeof(c),0);
fillchar(ddd,sizeof(ddd),0);
fillchar(dong,sizeof(dong),0);
for u:=1 to N do
for v:=1 to N do
begin
inc(c[v],a[u,v]);
inc(ddd[u],a[u,v]);
end;
ok:=true;
for k:=1 to N do
if (c[k]=0)or(ddd[k]=0) then ok:=false;
if ok then thu(1);
if ok then
begin
inc(sl);
writeln('*******:',sl,':*******');
writeln(f,'*******:',sl,':*******');
for u:=1 to N do
begin
for v:=1 to N do
begin
write(a[u,v],#32);
Tin học & Nhà trường 100 Đề Toán - Tin học