Page 33 - 17_26_INDRI WULANDARI_RIESKA KUSUMA PUTRI_12KGSP_BUKU UKUR TANAH
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Catatan :
= 180⁰00’00” -
Sudut lebih dari 180°
= 116⁰28’03” α1 = ( α + β ) - 180°
D 2.4 = 031⁰31’36” Sudut kurang dari 180°
= 170⁰00’54” + α1 = ( α + β ) + 180°
= 201⁰32’30” Sudut lebih dari 540°
= 180⁰00’00” - α1 = ( α + β ) - 540°
Maka hasil dari azimuth pasti
= 21⁰32’30”
bernilai positif
B) Perhitungan di titik P3
P3 = 087⁰35’25” D 3.2 = 148⁰31’42”
= 291⁰34’49” + = 291⁰34’49” +
= 379⁰10’14” = 440⁰06’31”
= 180⁰00’00” - = 180⁰00’00” -
= 199⁰10’14” = 260⁰06’31”
D 3.1 = 070⁰40’45” BP 3.3 = 259⁰46’55”
= 291⁰34’49” + = 291⁰34’49” +
= 362⁰15’34” = 551⁰21’30”
= 180⁰00’00” - = 540⁰00’00” -
= 182⁰15’34” = 11⁰21’44”
C) Perhitungan di titik P4
P4 = 173⁰40’49”
= 199⁰10’14” +
= 372⁰51’03”
= 180⁰00’00” -
= 192⁰16’14”
D 4.1 = 020⁰58’52”
= 199⁰10’14” +
= 220⁰09’06”
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