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Blast into Math!                                   Prime nummers: indestructimle muilding mlocks



               contains infinitely many elements. Therefore there must be some   j> k +1  such that


                                                             N
                                                    S j \{z n } n=1  = ∅.

                                                                   N   = ∅ . To do this we can use the set
               Let’s look for the smallest  j> k +1 such that S j \{z n }
                                                                   n=1
                                                                               N
                                 {j ∈ N such that j ≥ k +1 and S j \{z n }     n=1  = ∅}.

               This is a non-empty set of integers which is bounded below by k +1, so by the GLB Property it contains
               a unique smallest element. Let’s call it  g . Then


                                                             N
                                                    S g \{z n } n=1  = ∅,
               so there is m ∈ N  such that

                                                          N          m
                                                S g \{z n } n=1  = {s n } n=1 .


               Then we define

                                             z N+n = s n ,  for n =1,...,m.



               This sets the induction escalator into motion, proving the theorem.

                                                            ♥


               We can now use the Zipper Theorem to prove that the set of all rational numbers is countable.


               Theorem 5.4.5 The set of all rational numbers is countable.


               Proof: To use the Zipper Theorem we need to group the rational numbers into finite sets S k . We can

               do this with help from the Rational Theorem. Each rational number can be written as a quotient

                                                            p
                                                             ,
                                                            q


               with  p ∈ Z  and  q ∈ N . Let’s think about  |p| + q . Since  p ∈ Z  and  q ∈ N ,

                                                       |p| + q ≥ 1.



               For which rational number is  |p| + q =1? Since  q ∈ N ,  q ≥ 1, so the only way that

                                                       |p| + q =1







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