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Blast into Math! Analatic nummer theora: ants, ghosts and giants
Let’s look at the same ratio for the sequence
x n
x n = ,
(n +1)!
then
x n+1 n! x
x n+1
= = .
x n (n +1)! x n n +1
We know that x ∈ R , which means that x is either a rational number or the least upper
bound of a bounded set of rational numbers. In either case, there is some
m ∈ N such that m> x.
Then, if n ≥ 2m ,
x m 1
x n+1
= < < .
x n n +1 n +1 2
We can re-arrange this to
x n
x n+1 < , ∀n ≥ 2m.
2
Let’s think about this a bit more, and try to relate it further to a geometric series. We know that
x 2m x 2m+1 x 2m
x 2m+1 < , x 2m+2 < < .
2 2 2 2
Now you can prove by induction that
x 2m
x 2m+n < ∀n ∈ N.
2 n
So, now you can prove that the partial sums are all bounded, by splitting up the sum,
N n m n N n m n N−m
x x x x x m
S N = = + ≤ + , N ≥ m.
n! n! n! n! 2 n
n=0 n=0 m+1 n=0 n=1
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