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ATOMIC AND NUCLEAR PHYSICS


                   If the half-life of the radioactive element is T , then at the
                                                               1/2
                   end of this time the number of atoms in the sample will
                   become half i.e., 1/2. After a time 2T , i.e., after second half-
                                                      1/2
                   life  period,  the  number  of  remaining  atoms  will  become
                                2
                   1/2.1/2  =1/2   =1/4,  after  a  time  3  T ,  the  number  of
                                                          1/2
                                                               3
                   remaining atoms left will be1/2.1/2.1/2 =1/2  =1/8 ,  and at
                   the end of ‘t’ half lives number of atoms that remain will be
                       t
                   1/2 . It means that if N  is the original number of atoms in the
                                        o
                   sample  of  radioactive  element,  then  after  ‘t’  half-lives
                   number of atoms left in the sample can be determined by
                   using the relation,
                                                                   t
                                         Remaining atoms = Original atoms 1/2
                                                         t
                                                           or     N = N  x 1/2
                                                   o
                   The  process  of  radioactivity  does  not  depend  upon  the
                                                                  .
                   chemical combinations or reactions. It is also not affected by
                   any change in physical conditions like temperature, pressure,
                   electric or magnetic fields.                                         Be careful !

                   Example  18.2:  The  activity  of  a  sample  of  a  radioactive
                   bismuth  decreases  to  one-eight  of  its  original  activity  in
                   15 days. Calculate the half-life of the sample.

                   Solution:  Let  T ½   is  the  half-life  and  A   is  the  original
                                                            o
                   activity of the sample. After time T  activity will be  /2.
                                                                        A
                                                       ½
                                                                          o
                   After 2T  activity will become1/2.  /2=  /4. While after
                                                      A
                                                            A
                           ½                            o     o
                   time 3T , i.e., after three half-lives, the activity will drop   International  symbol  that
                           ½                                                     indicates  an  area  where
                   to  /8. It means activity drops to one-eighth of original A
                       o                                                         radioactive  material  is  being
                   activity in a time of 3 .T ½                                  handled or produced.
                   Therefore, 3T = 15. This means half-life T  of the sample will
                                ½
                                                           ½
                   be 5 days.
                   Example  18.3:  A  radioactive  element  has  a  half-life  of
                   40 minutes. The initial count rate was 1000 per minute. How
                   long will it take for the count rate to drop to (a) 250 per
                   minutes  (b)  125  per  minutes  (c)  Plot  a  graph  of  the    Radiation Treatment
                   radioactive decay of the element.                             Gamma  radiations  destroy
                   Solution: The initial count rate is 1000, therefore,          both  cancerous  cells  and
                                  40 min.
                                                          40 min.
                                              40 min.
                           1000                500                250                 125  healthy  cells.  Therefore,  the
                                                                                 beam  of  radiation  must  be
                                                                                 directed  only  at  cancerous
                   (a) As clear from above, it takes 2 half-lives for the count rate   cells.
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